Math, asked by NancyAmlani, 1 year ago

secA(1-sinA) (secA + tanA) =1. Prove that.​

Answers

Answered by chetansharma786
3

Step-by-step explanation:

secA(1-sinA)(secA+tanA)

= (1/cosA)(1-sinA)(1/cosA+sinA/cosA)

= (1/cos²A)(1-sinA)(1+sinA)

= (1/cos²A)(1-sin²A)

= (1/cos²A)(cos²A)

= 1

= RHS

This is the correct proof.

Plzz mark as brainlist:-) :-) :-)

Answered by MizZFaNtAsY
1

LHS

secA(1-sinA)(secA+tanA)  \\  \\  =  \frac{1}{cosA} (1-sinA)(secA+tanA)  \\  \\ = ( \frac{1}{cosA} - \frac{ sinA}{cosA} )(secA+tanA)  \\  \\ = (secA-tanA)(secA+tanA) \\  \\  =  {sec}^{2} A -  {tan}^{2} A\\  \\  = 1

RHS

=1

LHS=RHS

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