Question

SecA (1 + SinA) (SecA - tanA) = ?​

Answer 1

Step-by-step explanation:

Proof

Let us start with LHS

= (secA-sinA×secA)(secA+tanA)

=(secA-tanA) (secA+tanA) { secA=1/cosA and sinA/cosA=tanA}

= (sec²A-tan²A) { (a+b)(a-b)=a²-b²}

=sec²A-tan²A

=1

= RHS {using identity}

Hence proved

Answer 2

Answer:

Refer to above attachment

Step-by-step explanation:

Hope this help you