Question

secA=13/12 find cosA,SinA,cosecA,tanA,cotA​

Answer 1

given

secA=13/12

so cosA=12/13

we know

sinA=√1-cos²A

sinA=√1 - (144/169)

sinA=√25/169

sinA=5/13

so cosecA=13/5

tanA=sinA/cosA

tanA=(5/13)/(12/13)

tanA=5/13

so cotA=13/5