Math, asked by bhadraaditya50, 1 month ago

secA=13/5 then what is the value of cosecA? (1)​

Answers

Answered by pratzzchaudhry
1

Step-by-step explanation:

cosecA=

5

13

⇒sinA=

13

5

⇒cosA=

1−sin

2

A

=

1−

169

25

=

169

144

=

13

12

⇒cosA=

13

12

⇒secA=

12

13

⇒tanA=

cosA

sinA

=

13

12

13

5

=

12

5

Now, tan

2

A−sin

2

A=(

12

5

)

2

−(

13

5

)

2

=

144

25

169

25

=25[

169×144

169−144

]

=

169×144

25×25

& sin

2

Asec

2

A=(

13

5

)

4

×

(12)

2

(13)² =

(13) 2

.(12) 2

5×5×5 = 169×14425×25

Hence, tan 2

A−sin 2

A=sin 4

Asec 4 A

Hence, the answer is proved.

Answered by khushidas93
0

Answer:

Hey mate

Correct answer is 13/12.

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