Question

(secA - cosA) ×(Cota+TanA) = (secA×tanA )

Answer 1

(sec A - cos A)*(cot A * tan A)
= (1/cos A - cos A) * (sinA/cosA + cos A/sin A)
= (1-cos^2 A / cosA) * (sin^2 A + cos^2A / sin A cos A)
= ( sin^2 A / cos A ) * (1/ sin A cos A)
= ( sin A / cos ^2 A)
= sinA / cos A * 1/cos A
= tanA * sec A
= RHS

Hope this helps you !

Answer 2

(1/cosA - cosA) × (cosA/sinA + sinA/cosA)
add both separately I am skipping that step u can do it better☺
we get
(1-cos^2A/cosA) × (1/sinAcosA)
this gives
(sin^2A/cosA) × ( )
u know what empty bracket means here? right
then convert to sec and tan bro
u need to practice identities from Rd Sharma
solve all examples 2-2 times to master trigonometric identities