secA+cosecA = tanA +cotA
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tanA+cotA=secA.cosecA
I.e; tanA=(sinA/cosA) and cotA=(1/tanA)
.'.tanA+cotA=(sinA/cosA)+(1/(sinA/cosA)
.'.(sinA/cosA)+(cosA/sinA)
L.C.M
sin^2A+cos^2A/(cosA.sinA)
but.never forget your trigonometry identity that (sin^2A+cos^2A=1)
.'.(1/cosA)*(1/sinA)=1/(cosA.sinA)=secA.cosecA
I.e; tanA=(sinA/cosA) and cotA=(1/tanA)
.'.tanA+cotA=(sinA/cosA)+(1/(sinA/cosA)
.'.(sinA/cosA)+(cosA/sinA)
L.C.M
sin^2A+cos^2A/(cosA.sinA)
but.never forget your trigonometry identity that (sin^2A+cos^2A=1)
.'.(1/cosA)*(1/sinA)=1/(cosA.sinA)=secA.cosecA
jithu2327:
can write and show me please
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