Math, asked by monishchandravamsi, 10 months ago

SecA+sinA=2/3, then find sinA

Answers

Answered by tanish8251

Answer:

3/2-3cosA

Step-by-step explanation:

secA=1/cosA

1/cosA+sinA=2/3

1+sinAcosA/sinA=2/3

cross multiply

3+3sinAcosA=2sinA

3=2sinA-3sinAcosA

3=sinA(2-3cosA)

sinA=3/2-3cosA

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