Question

(SecA + tan A)/(Cosec(A) + CotA) - (SecA - tan A)/(CoseeA - CotA) = 2(SecA -Cosec(A))

Answer 1

Step-by-step explanation:

Sry mate I couldn't get it

Answer 2

Step-by-step explanation:

=((secA+tanA)(cosecA-cotA)-(secA-tanA)(cosecA+cotA))/. (cosec^2A-cot^2A)

=secA * cosecA - secA * cotA + tanA * cosecA - tanA * cotA - secA * cosecA - secA * cotA + tanA * cosecA + tanA * cotA

=2tanA * cosecA - 2secA * cotA

=2 (sinA/cosA)*(1/sinA) - 2 (1/cosA)*(cosA/sinA)

= 2(1/cosA - 1/sinA)

=2(secA - cosecA)