Seca-tana=1/2.
show that , SecA =5/4
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...............Here You Go Ur Answer............
╚═══❁═❀═✪═❀═❁════╝
hope it hel you....
mark me as brainliest
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Answer :
Given that,
secA - tanA = 1/2 ...(i)
We know that,
sec²A - tan²A = 1
or, (secA + tanA) (secA - tanA) = 1
or, (secA + tanA) * (1/2) = 1, by (i)
or, secA + tanA = 2 ...(ii)
Now, adding (i) and (ii), we get
2 secA = 1/2 + 2
or, 2 secA = 5/2
or, secA = 5/4
Hence, proved.
Have a good day :)
Given that,
secA - tanA = 1/2 ...(i)
We know that,
sec²A - tan²A = 1
or, (secA + tanA) (secA - tanA) = 1
or, (secA + tanA) * (1/2) = 1, by (i)
or, secA + tanA = 2 ...(ii)
Now, adding (i) and (ii), we get
2 secA = 1/2 + 2
or, 2 secA = 5/2
or, secA = 5/4
Hence, proved.
Have a good day :)
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