Question

(secA + tanA) ( 1 - sinA)​

Answer 1

Answer:

it is cos a.

Step-by-step explanation:

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Answer 2

Answer:

$\huge\underline{\overline{\mid {\bold {\green {☆ansWer☆}}\mid}}}$

$( \sec \: a + \tan \: a \: )(1 - \sin \: a)$

$= > \sec \: a \: + \tan \: a - \sec \: a \times \sin \: a - \tan \: a \times \sin \: a$

$= > \frac{1}{cos \: a} + tan \: a - tan \: a - \frac{ {sin}^{2} a}{cos \: a}$

$= > ( \frac{1}{cos \: a} ) - \frac{ {sin}^{2} a}{cos \: a}$

$= > \frac{1 - {sin}^{2} a}{cos \: a}$

$= > \frac{ {cos}^{2}a }{cos \: a}$

$= > cos \: a$