Math, asked by jayant4127, 10 months ago

(secA+tanA)(1-sinA)=
(a) secA
(b)sinA
(c)cosecA
(d)cosA

Answers

Answered by TheLifeRacer

5

Hii !

Solution :-

=> (SecA + tanA)(1-sinA)

=> (1/cosA+sinA/cosA)(1-sinA)

=> (1+sinA)(1-sinA)/cosA

=> 1-sin²A/cosA

=> cos²A/cosA = cosA Answer

____________________________

Hope it's helpful

#Rajukumar111

Answered by Jiteshsuvarnak

5

Answer

Step-by-step explanation:

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