Math, asked by ashusingla6879, 11 months ago

(SecA + TanA)(1-SinA) = CosA. Prove.

Answers

Answered by nikki8020
0

( SecA +TanA )(1-SinA)

= (1/CosA +SinA/CosA )(1-SinA)

={(1+SinA)/CosA}(1-SinA)

=[(1+SinA).(1-SinA)/CosA]

=[(1)^2 -SinA^2]/CosA

=CosA^2/CosA

=CosA {Proved}

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Answered by sanghamitra24
0

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