(secA+ tanA) (1-sinA ) is equal to
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=(1/cosA +sinA/CosA) (1-sinA)
={(1+sinA)/cosA} {1-sinA}
={(1+sinA)(1-sinA)/cosA}
=(1-sin²A)/cosA
=cos²A/cosA
=CosA (Ans)...
Hope it helped you a lot...
={(1+sinA)/cosA} {1-sinA}
={(1+sinA)(1-sinA)/cosA}
=(1-sin²A)/cosA
=cos²A/cosA
=CosA (Ans)...
Hope it helped you a lot...
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