(secA+tanA-1)/(tanA-secA+1)=cosA/(1-sinA)
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Step-by-step explanation:
(tanA+secA)-1/(tanA-secA)+1
={(tanA-secA)-1}(tanA-secA)/ (tanA-secA+1)(tanA-secA)
=(tan²A-sec²A)-(tanA-secA)/ (tanA-secA+1)(tanA-secA)
=-1-tanA+secA/(tanA-secA+1)(tanA-secA)
=-1/tanA-secA
=1/secA-tanA
=1/(1/cosA)-(sinA/cosA)
=1/(1-sinA/cosA)
=cosA/1-sinA
thank you..
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