Math, asked by harshjeswani321, 9 months ago

(secA-tanA)^2 = 1-sinA/1+sinA

Answers

Answered by sandy1816

1

Step-by-step explanation:

(secA-tanA)²

=(1-sinA/cosA)²

=(1-sinA)²/cos²A

=(1-sinA)/(1-sinA)(1+sinA)

=(1-sinA)/(1+sinA)

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