Math, asked by aashipatel2814, 1 month ago

( secA-tanA)²= 1-sinA/1+sinA​

Answers

Answered by shineemadhusree
0

Answer:

1-sinA/1+sinA x 1-sinA/1-sinA = (1-sinA)^2/1-sin^2A

= (1-sinA)^2/cos^2A

= [1/cos^2A-sin^2A/ cos^2A]^2

=[secA-tanA]^2

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