( secA-tanA)²= 1-sinA/1+sinA
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Answer:
1-sinA/1+sinA x 1-sinA/1-sinA = (1-sinA)^2/1-sin^2A
= (1-sinA)^2/cos^2A
= [1/cos^2A-sin^2A/ cos^2A]^2
=[secA-tanA]^2
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