Question

SecA+tanA=3 then secA=

Answer 1

secA+tanA=3
sec²A—tan²A=1
secA+tanA=1/3
secA=5/3

Answer 2

Given,      tan A = 3 - sec A ,       square that....

tan² A =  9 + sec² A - 6 sec A
           = 10 + tan² A - 6 sec A

so   sec A =  10/6 = 5/3