Question

secA+tanA=root 2 find secA-tanA

Answer 1

♧♧HERE IS YOUR ANSWER♧♧

Trigonometry is the study of angles and its ratios. This study prescribes the relation amongst the sides of a triangle and angles of the triangle.

There are sine, cosine, tangent, cot, sectant and cosec ratios to an angle of a triangle.

Let me tell you an interesting fact about Trigonometry.

"Triangle" > "Trigonometry"

Remember some formulae now :

sin²θ + cos²θ = 1

sec²θ - tan²θ = 1

cosec²θ - cot²θ = 1

Want to learn more!

Here it is :

sin(A + B) = sinA cosB + cosA sinB

sin(A - B) = sinA cosB - cosA sinB

cos(A + B) = cosA cosB - sinA sinB

cos(A - B) = cosA cosB + sinA sinB

SOLUTION :

We know that :

sec²θ - tan²θ = 1

=> (secθ + tanθ)(secθ - tanθ) = 1

=> √2 (secθ - tanθ) = 1

=> secθ - tanθ = 1/√2

So, secθ - tanθ = 1/√2

♧♧HOPE THIS HELPS YOU♧♧