Math, asked by missdhawan, 10 months ago

secA -tanA/secA+tan A = 1- 2secA +2tan²A

Answers

Answered by sandy1816

4

Step-by-step explanation:

secA-tanA/secA+tanA

=(secA-tanA)²/sec²A-tan²A

=sec²A-2secAtanA+tan²A

=1+tan²A-2secAtanA+tan²A

=1-2secAtanA+2tan²A

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