SecA+tanA / secA-tanA
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Answer:
1+sin²A/cosA = 1/cosA + sin²A/ cosA = secA + tanA.sinA
Step-by-step explanation:
- sec A= 1/cosA
tanA = sinA/cosA.
1/cosA + sinA/cosA /1/cosA- sin/CosA= 1+sinA/cosA / 1-sinA/cosA
= 1+sinA/ 1-sinA
squaring numerator and dinominator we get
1+sin²A / 1-sin²A
- 1-sin²A= cos²A
1+sin²A/cos²A
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