secA+tanA=x then secA-tanA=?
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Hey !!!
So simple xD
secA + tanA = x ------ 1 )
°•° sec²A - tan²A = 1
like a² - b² =( a - b ) ( a + b )
(secA - tanA ) ( secA + tanA ) = 1
x ( secA - tanA ) = 1 [from equation 1st secA + tanA = 1 ]
hence, secA - tanA = 1 /x Answer
_________________________
Hope it will help you !!!
@Rajukumar111 ®
So simple xD
secA + tanA = x ------ 1 )
°•° sec²A - tan²A = 1
like a² - b² =( a - b ) ( a + b )
(secA - tanA ) ( secA + tanA ) = 1
x ( secA - tanA ) = 1 [from equation 1st secA + tanA = 1 ]
hence, secA - tanA = 1 /x Answer
_________________________
Hope it will help you !!!
@Rajukumar111 ®
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