Question

sec@+tan@+1/tan@-sec@+1=1+sin@/cos@

Answer 1

hi , your solution is here
tanA + secA -1 / tanA -secA + 1 = (sinA +1-cosA) /(sinA+cosA-1 ) × (sinA+cosA +1)/(sinA+cosA+1)
= (sinA+cosA )(sinA-cosA)+sinA+cosA-cosA+1+sinA-cosA/(sinA+cosA)2-12)
...after simplification this is equal to
= 2sinA(1+sin A)/ 2sinA cosA
= (1+sin A)/ cosA
hence right side obtainnd