Math, asked by TbiaSupreme, 1 year ago

SecB=3/5 for some ∠B.State whether the given statement is true or false. Justify your answer.

Answers

Answered by gogiya167
0

 secb = \frac{3}{5}  can't be less than one hence this statement is false

because the minimum value of secb is 1. but 3/5 is less than one hence this statement don't support the argument.hence false.Or in the other point of view if

 secb = \frac{3}{5}  then  cosb = \frac{5}{3}  which is greater than one.We, know the maximum value of cosb is one.

which proves above statement is false.

Answered by MaheswariS
0

In the attachment I have answered this problem.

I have explained that the given statement is false with proper reasons.

See the attachment for detailed solution

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