Math, asked by chendu, 1 year ago

Second derivative of y=log(logx)

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Answered by kokan6515
10
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Answered by abhi178
3
y =log (logx )

differentiate wrt x

dy/dx ={1/logx}1/x =(xlogx)^-1

again differentiate wrt x

d^2y/dx^2 =-(xlogx)^-2 {logx + x 1/x }

= -(1 + logx )/(x. logx)^2

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