Question

second root of eq. ax^2+bx+c =0 is equal to nth power of first then prove that,
(ac^n)^1/n+1 + (a^nc)^1/n+1 +b =0​

Answer 1

Answer:

0

Step-by-step explanation:

Let the roots of the equation ax2+bx+c=0 be α,αn

Product of roots αn+1=ac

⟹α=(ac)n+11

Sum of roots α+αn=a−b

⟹(ac)n+11+(ac)n+1n=a−b

⟹a(ac)n+11+a(ac)n+1n+b=0

∴(anc)n+11