Second term of an arithmetic sequence is 18 and 4th 32 find more 1st and 3rd
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let a be first term and d be common difference
a + d = 18
a+ 3d = 32
2d = 14
d= 7
a= 11
1 st term = 11
3 rd term = a+ 2d
= 11 + 14
= 25
a + d = 18
a+ 3d = 32
2d = 14
d= 7
a= 11
1 st term = 11
3 rd term = a+ 2d
= 11 + 14
= 25
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