Question

Secondary School 

 

Math 

 

5 points

Divide 56 into 2 parts such that three times the first part exceeds one third of the second part by 48

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Answer 1

Answer:

20 , 36

Step-by-step explanation:

To find ----> Divide 56 into two parts such that three times the first part exceeds one third of the second part by 48 .

Solution----> Let two parts of 56 be x and y.

So , x + y = 56

y = 56 - x

Now, ATQ,

3 × First part = ( 1 / 3 ) × Second part + 48

=> 3 x = ( 1 / 3 ) y + 48

Multiplying whole equation by 3 .

=> 9x = y + 144

Putting y = 56 - x , in it , we get,

=> 9x = 56 - x + 144

=> 9x + x = 56 + 144

=> 10 x = 200

=> x = 20

Now , y = 56 - x

Putting x = 20 , in it , we get,

y = 56 - 20

y = 36