Question

Secs+tana-1/tana-seca-1=1+Sina/cosa

Answer 1

seca
$\frac{ \sec( \alpha ) + \tan( \alpha ) - 1 }{ \tan( \alpha ) - \sec( \alpha ) - 1 } = 1 + \frac{ \sin( \alpha ) }{ \cos( \alpha ) }$