Question

sectheta-costheta =sin^2theta/costheta how it possible​

Answer 1

$\sec(x ) - \cos(x) = \frac{ { \sin }^{2} (x)}{ { \cos}^{2}(x) } \\ \sec(x) - \cos(x) \\ \frac{1}{ \cos(x) } - \cos(x) \\ \frac{1 - { \cos }^{2}(x) }{ \cos(x) } \\ \frac{ { \sin}^{2} (x)}{ \cos(x) }$