Question

SECTION-B
6. If 1 is a zero of polynomial P(x) = ax2 - 3(a - 1) - 1, then find the value of a.​

Answer 1

Answer:

Given,

p(x)=ax^2-3(a-1)-1

Zero of p(x)=1

Now,

p(1)=0

=> a1^2-3(a-1)-1=0

=> a-3a+3-1=0

=> a-3a+2=0

=> -2a+2=0

=> -a=-2/2

=> -a=-1

=> a=1

.·. The value of a is 1.

Answer 2

Answer:

1

Step-by-step explanation:

p(x)=ax^2-3(a-1)-1

=ax^2-3a+3-1

=ax^2-3a+2

p(1)=0

a(1)^2-3a+2=0

a-3a+2=0

-2a=-2

a=1