Question

SECTION B
Solve for x : log2 + log ( x + 3) - log ( 3x - 5) = log3
Q. 4​

Answer 1

log a+log b= log a×b

So

log2+log(x+3)= log 2(x+3)= log2x+6----- (1)

AND

log a - log b = log a/log b

log a= (substituting 1)

log b = log 3x-5

So

log2x+6 - log3x-5 = log2x+6/log3x-5 = log3

So 2x+6/3x-5 = 3

2x+6= 9x-15

7x=21

Therefore x=3

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