Question

Section-
Q11. For what value of 'k' the points (14.-4), (5,1) and (3,k) are collinear?​

Answer 1

Answer:

k = 6

Step-by-step explanation:

let,

(14,4) = x1, y1

(5,1)= x, y

(3,k)= x2, y2

As points are collinear they all lie in same line

by using midpoint formula

y = y1 + y2/2

1= -4 + k/ 2

1*2= -4+k

2=-4+ k

2+4= k

.: k = 6

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