Question

secX+tanX=P prove that sinX=(p^2-1)/(p^2+1)​

Answer 1

Step-by-step explanation:

secA+tanA=p______(1)

sec²A-tan²A=1

(secA+tanA)(secA-tanA)=1

p(secA-tanA)=1

secA-tanA=1/p_____(2)

(1)+(2)

secA+tanA+secA-tanA=p+1/p

2secA=(p²+1)/p

secA=(p²+1)/2p

(1)-(2)

secA+tanA-(secA-tanA)=p-1/p

secA+tanA-secA+tanA=(p²-1)/p

2tanA=(p²-1)/p

tanA=(p²-1)/2p

tanA/secA=(p²-1)/2p÷(p²+1)/2p

sinA=(p²-1)/(p²+1)