Question

see carefully and give the answer this lock down time ​

Answer 1

$\mathfrak{\large{\underline{\underline{Answer :-}}}}$

The answer is 144.

$\mathfrak{\large{\underline{\underline{Explanation :-}}}}$

$\textbf{\large{\underline{Statement I}}}$

$\boxed{\sf{Shoes+Shoes+Shoes=60}}$

Consider only a single shoe as ‘S’. As they are given in pairs, the value of shoes will be 2s in the first Statement.

⇒ 2s + 2s + 2s = 60

⇒ 6s = 60

⇒ s = 60/6

⇒ s = 10

Value of one shoe is 10

Value of the pair of shoes =

⇒ 10 × 2

⇒ 20

$\rule{300}{1.5}$

$\textbf{\large{\underline{Statement II}}}$

$\boxed{\sf{Shoes+Boy+Boy=30}}$

Consider the Boy as ‘b’. Place the value of pair of shoes as they are given in pairs.

⇒ 20 + b + b = 30

⇒ 20 + 2b = 30

⇒ 2b = 30 - 20

⇒ 2b = 10

⇒ b = 10/2

⇒ b = 5

The Value of the Boy is 5

$\rule{300}{1.5}$

$\textbf{\large{\underline{Statement III}}}$

$\boxed{\sf{Sunglasses+Boy+Sunglasses=9}}$

Consider the Sunglasses as ‘n’. Place the value of Boy in the Statement.

⇒ n + 5 + n = 9

⇒ 2n + 5 = 9

⇒ 2n = 9 - 5

⇒ 2n = 4

⇒ n = 4/2

⇒ n = 2

Value of Sunglasses is 2

$\rule{300}{1.5}$

$\textbf{\large{\underline{Statement IV}}}$

$\boxed{\sf{Shoes+Gloves+Sunglasses=42}}$

Consider Gloves as ‘g’. Place the value of Shoes (Pair) and Sunglasses.

⇒ 20 + g + 2 = 42

⇒ 22 + g = 42

⇒ g = 42 - 22

⇒ g = 20

The value of Gloves is 20.

$\rule{300}{1.5}$

$\textbf{\large{\underline{Statement V}}}$

$\boxed{\sf{Shoe+Boy \times Sunglasses=??}}$

Look at the Statement carefully ! The Shoe is single here and is not in pair. The boy not only carries its value but in actual, the boy is wearing Sunglasses, pair of Gloves and pair of shoes.

• Value of Single Shoe = 10
• Value of Boy = 5
• Value of Sunglasses = 2
• Value of Gloves = 20

★ Single Shoe + (Boy + Sunglasses + Pair of Shoes + Pair of Gloves) × Sunglasses = ??

⇒ 10 + (5 + 2 + 20 + 40) × 2

Solve According to BODMAS

⇒ 10 + 67 × 2

⇒ 10 + 134

⇒ 144

The answer is 144.

Answer 2

$\huge {\pink{\mathfrak{Solution :-}}}$

$\rule{197}{1}$

$\underline{\bold{In\:First \:Statement:}}$

$\boxed{\boxed {\blue {\tt{Shoes+Shoes+Shoes=60}}}}$

Let a single shoe be x. As we know that, they are given in pairs (means they are two in number) so, the value of shoes will be 2x in the first Statement.

$\leadsto 2x+ 2x + 2x= 60\\\\ \leadsto 6x = 60\\\\ \leadsto x =\frac{60}{6}\\\\ \leadsto x=10$

Value of single shoe is 10.

$\sf {The\:value\: of \:the\: pair\: of \:shoes = 10\times 2=20}$

$\rule{197}{1}$

$\underline{\bold{In\:Second\:Statement :}}$

$\boxed{\boxed{\blue{\tt{Shoes+Boy+Boy=30}}}}$

Let the boy be y .Put the value of pair of shoes as they are given in pairs.

$\leadsto 20 + y + y= 30\\\\ \leadsto 20 + 2y =30\\\\ \leadsto 2y= 30 - 20\\\\ \leadsto 2y= 10\\\\ \leadsto y= \frac {10}{2}\\\\ \leadsto y= 5$

$\sf {The\: Value \:of the\: boy\: is \:5.}$

$\rule{197}{1}$

$\underline{\bold{In\:Third\:Statement: }}$

$\boxed{\boxed{\blue {\tt {Sunglasses+Boy+Sunglasses=9}}}}$

Let the Sunglasses be z. Put the value of Boy in the statement.

$\leadsto z+ 5 + z = 9\\\\ \leadsto 2z + 5 = 9\\\\ \leadsto 2z = 9 - 5 \\\\ \leadsto 2z=4\\\\ \leadsto z = \frac {4}{2} \\\\ \leadsto z= 2$

$\sf {The\:Value \:of \:Sunglasses \:is\: 2.}$

$\rule{197}{1}$

$\underline{\bold{In\:Fourth\:Statement :}}$

$\boxed{\boxed{\blue{\tt{Shoes+Gloves+Sunglasses=42}}}}$

Let Gloves be n. Put the value of Shoes (Pair) and Sunglasses.

$\\\\ \leadsto 20+n+ 2 = 42\\\\ \leadsto 22 +n= 42\\\\ \leadsto n = 42 - 22\\\\ \leadsto n= 20$

$\sf {The\: value \:of \:Gloves\:is\:20.}$

$\rule{197}{1}$

$\underline{\bold {In\:Fifth\:Statement: }}$

$\boxed{\boxed {\blue{\tt{Shoe+Boy \times Sunglasses=??}}}}$

We can see that the Shoe is single and is not in pair. The boy is not only having its value but actually, the boy is wearing Sunglasses, pair of Gloves and pair of shoes.

• Value of Single Shoe = 10
• Value of Boy = 5
• Value of Sunglasses = 2
• Value of Gloves = 20

Single Shoe + (Boy + Sunglasses + Pair of Shoes + Pair of Gloves) × Sunglasses:

$10 + (5 + 2 + 20 + 40) \times2$

Solving by using BODMAS rule :

$\longrightarrow 10 + 67 \times 2\\\\ \longrightarrow 10 + 134 \\\\ \longrightarrow 144$

$\green{\therefore{\bf{The\:obtained \:answer \: is\: 144. }}}$

$\rule{197}{2}$