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If the given line segment is divided by y axis than x coordinate will be 0.
So the coordinate of point of intersection Will be (0,y)
1) Ratio in which AB is divided by y axis.
Let the ratio as lamda : 1
Using internal divison formula.
0 = x2m1+ x1m2/ lamda+1
0 = 8lamda + (-4 )(1)/lamda +1
0 = 8 lamda -4
4 = 8 lamda
4/8 = lamda/1
1/2 = lamda/ 1
so ratio = 1:2
2) Co ordinate of point of intersection.
Using internal divison formula.
We have already x = 0 ( prove above)
y = y2m1 + y1m2/ m1+ m2
y = -3(1) +6(2)/1+2
y = -3+12/3
y = 3
So co ordinate are 0,3
3) Length of AB
Using distance formula.
AB = √( x2 - x1)^2 + (y2- y1)^2
AB = √(8-(-4)^2+[(-3)-6]^2
= √144+81
AB = 15 unit.
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