Question

see the attachment and solve it ​

Answer 1

Answer:

$\sqrt{2 {}^{2} + 1 {}^{2} }$

=

$\sqrt{5}$

sin thetha = opposite / hypotenuse

=

$2 \div \sqrt{5}$

similarly

cos theta = addjacent/hypotenuse

=

$1 \div \sqrt{5}$

now substituting we get the value

answer as 4.2

Answer 2

21/5

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