Question

see the pic and give the solution​

Answer 1

Answer:

${2x}^{2} + 13x \: - 6 = 0$

Kindly refer to the Attachment

Step-by-step explanation:

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Answer 2

$\frac{x-1+2x-4}{x^{2} -x-2x+2}=\frac{6}{x} \\ \\\frac{3x-5}{x^{2} -3x+2}=\frac{6}{x}\\ \\3x^{2} -5x=6x^{2} -18x+12\\\\6x^{2} -3x^{2} -18x+5x+12=0\\\\3x^{2} -13x+12=0\\\\3x^{2} -9x-4x+12=0\\\\3x(x-3)-4(x-3)=0\\\\(3x-4)(x-3)=0\\\\x=4/3\\\\Or,\\\\x=3$

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