see the pic.... now tell me how can I find the slant height of that cone
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Answered by
3
here h=12r/5........eq1
putting value of r in eq1
h=12
h^2+r^2=l^2
where l=slant height
12^2+5^2=l^2
144×25=l^2
169=l^2
13=l
then slant height = 13m
hope it will help you
thanks
putting value of r in eq1
h=12
h^2+r^2=l^2
where l=slant height
12^2+5^2=l^2
144×25=l^2
169=l^2
13=l
then slant height = 13m
hope it will help you
thanks
Answered by
2
your answer.........
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