Math, asked by s17920932, 2 months ago

See the problem
42 sq. cm
14 sq. cm
С
А
M
28 sq. cm
B.
The ratio of areas of triangles lies above the diagonal AC of the quadrilateral on the
figure.
= 42:14
3:1
If MC= 7 cm, then
AM
=
cm
What is the area of triangle AMB?
If DM = 5 cm, then
cm
BM​

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Answers

Answered by s1239ankit9875
10

Answer:

Here MC = 7 cm (Given)

And area of triangle DMC = 14 cm ²

1/2MC*MD= 14

1/2*7*MD= 14

14*2/7= MD

4 cm = MD

Now Area of triangle ADM = 42 cm ²

1/2*MD*AM = 42 cm ²

1/2*4*AM = 42 cm ²

2AM = 42 cm ²

AM = 42/2 = AM = 21 cm

Area of triangle BMC = 28 cm ²

1/2*BM*MC= 28 cm ²

1/2 *BM*7= 28

28*2/7= BM= BM = 8 cm

Area of triangle AMB = 1/2*BM* AM

1/2*8*21= 84 cm ²

Answered by sapnakalikkodan
0

Answer:

ഇത് കുറച്ച് tuff ആണല്ലോ

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