Question

See the question in Photo and answer
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Answer 1

Answer:

The measure of  $\angle BDC$ is $25^o$

Step-by-step explanation:

We know that angles in the same segment are equal. So,

$\angle BED= \angle BAD=65^o$

Also, the angle in a semicircle is $90^o$. Thus we have

$\angle ADB=90^o$

The sum of angles in a triangle is $180^o$. So,

$\angle ADB+\angle BAD+\angle DBA=180^o\\\\\implies 90^o+65^o+\angle DBA =180^o\\\\ \implies \angle DBA=180-65-90= 25^o$

The lines AB and DC and parallel. So

$\angle DBA=\angle BDC$

being alternate angles.

Hence we get,

$\angle BDC=25^o$

Option (d) is the correct choice.