Question

See who will solve this easy problem. The person who gives the perfect answer he will be BRAINLIEST.


PLS ITS URGENT.

Answer 1

Hey friend hope this will help you.............

Given we square side=14/3 m

hence perimeter of quare(p1)=4*side
= 4*(14/3)
=56/3m
=18.667 m

Also given rectangle length (l)=26/5 m

breadth(b)= 17/3 m

hence perimeter of rectangle (p2)=2*(l+b)

=2*[(26/5) + (17/3)]

=2*10.86667

= 21.73334 meter

Hence p2>p1

hence perimeter of rectangle is greater

Answer 2

Answer:

Hey friend hope this will help you.............

Given we square side=14/3 m

hence perimeter of quare(p1)=4*side

= 4*(14/3)

=56/3m

=18.667 m

Also given rectangle length (l)=26/5 m

breadth(b)= 17/3 m

hence perimeter of rectangle (p2)=2*(l+b)

=2*[(26/5) + (17/3)]

=2*10.86667

= 21.73334 meter

Hence p2>p1

hence perimeter of rectangle is greater