Math, asked by sarthakh8118, 4 days ago

Seema is now 15 years older than her younger brother Sanjay. Ten years from now, she will be twice as old as Sanjay. Taking Sanjay's present age to be x years, (i) An expression for Seema's present age will be: (a) (x - 15) (b) 15 x (c) (x + 15) ( (d). What will be expression Sanjay's age after 10 years? (a) (x + 10) (b)(x - 10) (c) 10x (d) (x + 20) (iii) Expression representing Seema's age after 10 years: (a) (x + 25) (b) (x + 10) (c) (25x) (d) (x + 15) (iv) Seema's present age will be: (a) 25 years (b) 20 years (c) 10 years (d) 30 years​

Answers

Answered by mallepallijoshnaredd
0

Answer:

20 years I did it on my own

Step-by-step explanation:

the question is wrong it should be like ten years from now,sheila will be twice as old as sanjay

Let the Present age of Sanjay (in Years ) = x

Therefore , Present age of Sheila = x+15

After 10 years ,

Shielas age = x+15+10

= x+25

sanjay's age = x+10

According to question ,

x+25 = 2(x+10)

x+25 = 2x + 20

25 = 2x + 20 - x

25 = x+20

25 - 20 =x

5 =x

or x=5

Hence Present age of Sanjay = 5 years

and Present age of Shiela = x+15

= 5+15

= 20 years

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