Math, asked by nigam3400p8782g, 1 year ago

Seema took a loan of rupees 8596 from the bank she pays back rupees 9286 to the bank what amount did she pay back as interest to the bank Seema was able to repay the loan in 2 months and she paid equal amounts in 2 months what amount did she pay in a month

Answers

Answered by madeducators3
38

Given:

Seema took a loan of Rs 8596.

She pays back Rs 9286 to the bank

She paid the amount in 2 months and paid equal about in 2 months.

To Find:

Find the interest she paid to the bank and the amount she paid in a month.

Solution:

Seema took a loan of RS 8596

She pays back Rs 9286

Amount she paid as interest = 9286-8596= Rs 690

Simple interest = S.I=\frac{(P)(r)(t)}{100}

P = Rs 8596

r ?

t= 2 months

S.I = Rs 690

690= \frac{8596(r)(1)}{6(100)}

r = 48%

Amount paid in both the month is same.

total amount paid as an interest = 690.

Total amount paid = Rs 9286

Amount paid in 1 month = half of 9286

                                      = Rs 4643

Amount she paid as interest = Rs 690

Amount she paid in 1 month = Rs 4643

Answered by gargs4720
16

Answer:

Seema took a loan of Rs8596

She pays back Rs9286

Amount she paid as intrest= 9286-8596

=690

SI = (P)(R)(T)

100

P=8596

R=?

T=2MONTHOS

SI=RS690

690= 8596(r)(1)

6(100)

AMOUNT PAID IN BOTH THE MONTH IS SAME

TOTAL AMOUNT PAID AS THE INTREST =690

AMOUNT PAID IN 1MONTH = HALF OF 9286

=RS4643

AMOUNT SHE PAID AS INTRESET = RS690

AMOUNT SHE PAID IN 1MONTH = RS4643

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