Math, asked by yadavsurendra997, 10 months ago

Seema want
ma wants to invest 5400 into two parts such that interest on the
two parts such that interest on the first part for 4
vears at 5% p.a. is equal to the interest
interest on the second part for 2 years at 15% p.a. Find the
amount invested in both the parts.

Answers

Answered by StudyToxic
11

The two parts are 3240 and 2160...

Attachments:
Answered by FelisFelis
14

The amount invested in first part is 3240 and the amount invested in second part is 2160.

Step-by-step explanation:

Consider the provided information.

Let Seema invest x rupees on the first part for 4  years at 5% p.a.

That means on the second part she invest 5400-x.

The formula to calculate the Simple interest is: S.I=\frac{p\times r\times t}{100}

According to question on the first part for 4  years at 5% p.a. is equal to the interest  interest on the second part for 2 years at 15% p.a.

Therefore,

\frac{x\times 5\times 4}{100}=\frac{(5400-x)\times 15\times 2}{100}

x\times 5\times 4=(5400-x)\times 15\times 2

2x=3(5400-x)

2x=16200-3x

5x=16200

x=3240

The amount invested in first part is 3240.

The amount invested in second part is 5400-3240=2160.

#Learn more

How much time for an amount of 450 to yeild 81 as interset at 4.5% per annum of simple interset

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