Seeta and geeta cycled towards each other, one from point a and the other from point b, respectively. seeta left a 6 hours later than geeta left point b, and it turned out on their meeting that seeta had travelled 12km less than geeta. after their meeting, they kept cycling with same speed, and seeta arrived at b 8 hours later and geeta arrived at a 9 hours later. find speed of the faster cyclist.
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let they meet at point X.From the question i concluded that first cyclist is fastest. let the time and distance taken by first cyclist be (t−6)(t−6) hrs and (m)(m) km to travel upto point X
let the time and distance taken by second cyclist be (t)(t) hrs (m+12)(m+12) km to travel upto point Xi used the formula that
if two persons starting from point x and y with speed s1 s1 ans s2 s2 coming towards each other from opposite direction after meeting each other take time t1 t1 and t2t2 to reach points y and x respectively thens1s2=t2t1−−√s1s2=t2t1and i concluded.mt−6m+12t=98−−√mt−6m+12t=98. now stucked for two unknowns.
let the time and distance taken by second cyclist be (t)(t) hrs (m+12)(m+12) km to travel upto point Xi used the formula that
if two persons starting from point x and y with speed s1 s1 ans s2 s2 coming towards each other from opposite direction after meeting each other take time t1 t1 and t2t2 to reach points y and x respectively thens1s2=t2t1−−√s1s2=t2t1and i concluded.mt−6m+12t=98−−√mt−6m+12t=98. now stucked for two unknowns.
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