Physics, asked by princera5mi, 1 year ago

Seeta is moving due east with a velocity of v1 m/s and Geeta is moving due west with a velocity of v2 m/s. The velocity of Seeta with respect to Geeta is: a) V1+V2 due east b) v1-v2 due east c) v1-v2 due west d) v1+v2 due west. This question was asked in my weekly test.

Answers

Answered by Anonymous
7
The correct option is is 'a' , I think so...

Answered by syed2020ashaels
0

Answer: The correct answer is option (a) V1+V2 due east

Explanation:

According to the given information,

Seeta is moving due east with a velocity of v1 m/s and Geeta is moving due west with a velocity of v2 m/s.

They are moving with different speeds that is v1 and v2, and they are moving in opposite directions. This means that the velocity one Seeta relative to Geeta will be v1+v2 m/s .

This occurs according to the definition of relative velocity of two bodies.

Hence, when Seeta is moving due east with a velocity of v1 m/s and Geeta is moving due west with a velocity of v2 m/s. The velocity of Seeta with respect to Geeta is: a) V1+V2 due east .

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