Question

seg AB and seg CD intersect each other at point M if AM × MD = CM × MB then show that angle CAB = angle DBA.

Answer 1

Proved below.

Step-by-step explanation:

Given:

$AM\times MD=CM \times MB$

$\frac {AM}{CM}=\frac {MB}{MD}$  

To prove:

angle CAB = angle DBA

Proof:

In ΔAMC and ΔBMD

$\frac {AM}{MC}=\frac {BM}{MD}$      [given]

∠ AMC = ∠BMD  [ vertically opposite angles]

$\triangle AMC \sim \triangle MBD$ [by SAS similarity ]

By corresponding parts of similar triangles.

∠ CAM = ∠ DBM

⇒ ∠ CAB = ∠ DBA

Hence prove.

Answer 2

please marke as brinalist

I hope this answer is help you...