Question

question number 21 and answer

Answer 1

In rectangle ABCD AB=36 and BC= 24
so AD= 24 and DC=36
now
area of the triangle ADE
$= \frac{1}{2} \times base \times height \\ = \frac{1}{2} \times 24 \times 15 = 180 \: {m}^{2}$
now area of the rectangle ABCD
$= length \times breadth = 36 \times 24 \\ = 864 \: {m}^{2}$
now area of the shaded region be
=area of the rectangle ABCD - area of the triangle ADE
=864-180= 684 m²

Answer 2

Area of shaded reglon=Area of rectangle-Area of triangle
=l×b-(1/2×b×h)