seg AB is daimeter of circle and point C is curcumference angle B is less by 10degre than algle A find the measure of all angles of triangle ABC
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angle ACB=90 degree (angle of semicircle)
angle ABC= angle BAC - 10
As, angle ABC + angle BCA+ angle BAC=180
(angle ABC )+( 90)+ (angle ABC +10)=180
2* angle ABC = 180-100
angle ABC= 80/2=40 degree
angle ABC= angle BAC - 10
As, angle ABC + angle BCA+ angle BAC=180
(angle ABC )+( 90)+ (angle ABC +10)=180
2* angle ABC = 180-100
angle ABC= 80/2=40 degree
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