Question

seg AE perpendicular side BC,seg PM perpendicular line BC if AE =12,PM=16 finds triangle ABC or triangle PBC
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Answer 1

Given : seg AE perpendicular side BC,

seg PM perpendicular line BC  

AE =12,PM=16

To find : Ar (Δ ABC )  / Ar (Δ PBC )

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Solution:

Area of triangle = (1/2) * Base * Height  

Ar (Δ ABC ) = (1/2) * BC  * AE

Ar (Δ PBC ) = (1/2) * BC  * PM

Ar (Δ ABC )  / Ar (Δ PBC )   =    (1/2) * BC  * AE /  (1/2) * BC  * PM

=> Ar (Δ ABC )  / Ar (Δ PBC )   =     AE /   PM

=> Ar (Δ ABC )  / Ar (Δ PBC )   =     12  /   16

=> Ar (Δ ABC )  / Ar (Δ PBC )   =   3  /  4

Ar (Δ ABC )  / Ar (Δ PBC )   =   3  /  4

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